problem no 56:(problem on Strings):Given two strings A and B. Find the characters that are not common in the two strings.

 QUESTION:

Uncommon characters

Basic Accuracy: 30.87% Submissions: 2461 Points: 1

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Given two strings A and B. Find the characters that are not common in the two strings. 

Example 1:

Input:
A = geeksforgeeks
B = geeksquiz
Output: fioqruz
Explanation: 
The characters 'f', 'i', 'o', 'q', 'r', 'u','z' 
are either present in A or B, but not in both.

Example 2:

Input:
A = characters
B = alphabets
Output: bclpr
Explanation: The characters 'b','c','l','p','r' 
are either present in A or B, but not in both.

Your Task:  
You dont need to read input or print anything. Complete the function UncommonChars() which takes strings A and B as input parameters and returns a string that contains all the uncommon characters in sorted order. If no such character exists return "-1".

 

ANSWER:

 String UncommonChars(String A, String B)
    {
        int arr1[]=new int[128];
          int arr2[]=new int[128];
        for(int i=0;i<128;i++)
        {
            arr1[i]=0;
            arr2[i]=0;
        }
       
        for(int i=0;i<A.length();i++)
        {
            arr1[(int)A.charAt(i)]=arr1[(int)A.charAt(i)]+1;
        }
       
       
         for(int i=0;i<B.length();i++)
        {
            arr2[(int)B.charAt(i)]=arr2[(int)B.charAt(i)]+1;
        }
       
        String s="";
            for(int i=0;i<128;i++)
        {
        
            if(arr1[i]>0 && arr2[i]==0)
            {
                 s=s+(char)i;
            }
            if(arr2[i]>0 && arr1[i]==0)
            {
                s=s+(char)i;
            }
        }
        if(s.length()==0)
        {
            return "-1";
        }
        else
        {
       return s;    
        }
       
    }